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Bridge Winners Profile for Sasha Cooper

Sasha Cooper
Sasha Cooper
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Basic Information

Member Since
Aug. 17, 2014
Last Seen
4 hours ago
Member Type
bridge player

Bridge Information

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Emily Middleton's bidding problem: AKT643 A9 --- QJ963
We'd be unlucky to go off in 5 (partner having neither the A, K or A or a stiff heart for his values-showing bid), so I'd just re-cue diamonds.
Peg Kaplan's lead problem: 32 T T9xx A98xxx
I think declarer's 6 was silly. What's wrong with a good old fashioned 5N?
Yuan Shen's bidding problem: K5 QT7 KQ6 K9853
I like 3 not in case P can pass it, but because we're not making unless he has the A, so if I deny values in the suit he should cue 3 only if he has some, then I can bid 3N with a reasonable expectation ...
Sasha Cooper's bidding problem: 97 T53 J943 J642
The same thought went through my head at the time, though I wonder if it does make sense to play it that way - with a decent spade stop and any kind of other values I'd have responded 1N, and with a spade stop and nothing else it would surely ...
Sasha Cooper's bidding problem: A3 AQJ7 AKQ5 K85
There isn't really a standard version - there seem to be as many Fantunes variants as there are Fantunes partnerships. The NT rebid structure is irrelevant here anyway
Sasha Cooper's bidding problem: 97 T53 J943 J642
I'm not really sure about the margins, since oddly it's quite a rare sequence :P The minimum I would expect opener to have to even think of Xing is something like x AQJx AQx AQxxx. But I don't think it would be right to X into a ...
Sasha Cooper's bidding problem: 97 T53 J943 J642
Maybe. It seems likely to have almost no play if responder doesn't have the KH, though, whereas 4 might be making opposite a suitable Yarborough. I'll post it as a separate problem.
Sasha Cooper's bidding problem: 97 T53 J943 J642
It feels resultsy, but the reason for posting this was to see whether anyone thought there was a case for passing this. P had A3 AQJ7 AKQ5 K85 Overcaller had KJ862 8642 T7 Q3 and advancer QT54 K9 862 AT97 So 3 was probably off 2, and 4 ...
Sasha Cooper's bidding problem: 97 T53 J943 J642
In order: 1) Yes 2) Up to 37 HCP*, or more if you can feign ignorance of the 14th card 3) An unlimited and unbalanced hand with diamonds 4) Not well defined, but he would have to consider passing many balanced 19 counts, and possibly stronger hands, depending on how ...
Jordan Lampe's bidding problem: AJ6 732 KJ2 AT76
I like 5N, because I don't actually care if it's passing the buck or 'pick a slam'.

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