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Bridge Winners Profile for Owen Lien

Owen Lien
Owen Lien
  • 24
    Following
  • 163
    Followers
  • 22
    Posts
  • 8
    Favorites

Basic Information

Member Since
June 20, 2010
Last Seen
March 26
Member Type
Bridge Player
Country
United States of America

Bridge Information

Favorite Bridge Memory
3rd in the Blue Ribbon Pairs in 2015
Bridge Accomplishments
5000 mini spingold champ; 3rd in BRP 2015; 1st in 0-10K swiss 2016
Regular Bridge Partners
Zach Brescoll, Zach Wasserman
Member of Bridge Club(s)
The Bridge Connection - Southfield, MI
Favorite Tournaments
Atlanta Labor Day Regional, Charleston/Myrtle Beach Christmas Regional
Favorite Conventions
Flannery!
BBO Username
olien
ACBL Ranking
Emerald Life Master
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Do defensive beers count if diamonds are trumps?
Too bad :(
Do defensive beers count if diamonds are trumps?
I imagine that Marc will make one of the 8 a dubbel just for you :)
Do defensive beers count if diamonds are trumps?
Well - it was redoubled. If an undoubled defensive beer counts as two...that’s where re arrive at 8
Do defensive beers count if diamonds are trumps?
Actually, we’re in the same camp. I offered to produce the poll.
Do defensive beers count if diamonds are trumps?
For those who don’t know - it was a redoubled contract
Criss -cross Inverted Raises
Lee, I could not agree more. Inverted minors preclude one of my maxims of bridge: support with support, by rendering unavailable responder’s simple raise. They also mitigate responder’s problem (in the context of 1D = 4+) of what to respond with single-bid values and xy3=6 (when x<4 ...
Criss -cross Inverted Raises
I agree with that sentiment in a regular partnership. However, in a one-off or infrequent partnership, I think that disambiguating INV and GF makes things more clear-cut as neither partner should be in doubt as to what level to which the auction is forced. I’ve experienced far too many ...
Criss -cross Inverted Raises
IMO, Reitman is the right man, again
Owen Lien's bidding problem: Kx ATxx x AKQTxx
I like natural
Owen Lien's bidding problem: Kx ATxx x AKQTxx
3 by responder would’ve been NF. It’s basically natural bidding (2 = 5+, F1; 4th suit GF; etc) and 2NT is “NAT” F1 (basically GF unless O re-bids 3♣)
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