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Bridge Winners Profile for Andrzej Matuszewski

Andrzej Matuszewski
Andrzej Matuszewski
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Basic Information

Member Since
July 21, 2012
Last Seen
10 hours ago
Member Type
Bridge Player
about me
Statistician with interests in: sociology, history, psychology, pure mathematics, ecology and MUSIC

Bridge Information

Regular Bridge Partners
Jerzy Orysiak, Tadeusz Skalski, Roman Krzemien
ACBL Ranking
subjective Standard Polish Club
Copy to my cards View/Print
Bridge sometimes is very strange! I did not tell nor ask you what are you going to put for a second spade from dummy. Yes you are in a sort of squeeze in the second trick. It seems that a good solution is to dump a CLUB. East correctly assumed ...
It is important that you play at MPs....
Andrzej Matuszewski's bidding problem: J875 AQ82 AJ AJ4
My hint is the following: How it is possible that W in unfavorables bids? Probability that he has void in hearts is close to 50%. And it is not easy to play hearts at 0-4 division...
Tommy Cho's bidding problem: AJ3 AJ954 A7 AJ7
Does he propose me the choice between hearts and a minor?
Jerry Murbach's bidding problem: KQ32 T92 J2 AQ76
My pd has void in spades (at MPs such T/O double is possible) while S should have void in clubs.
Andrzej Matuszewski's bidding problem: Q742 AJ7 A KJ984
Thanks Brad and Gregory for discussion in a very difficult topic!!! My "solution" is the following. Pd has at most: 2 hearts, 2 spades and 3 clubs. So he has at least 6 diamonds. So I must pass!!! Additionally i have very good first lead: A!!!
MPs squeeze
If you cashed 5 rounds of hearts and no diamonds appeared - cashing diamonds seems to be ineffective since you can not establish them...
Andrzej Matuszewski's bidding problem: Q742 AJ7 A KJ984
Without any agreement: pd's pass means that he didn't has a safe bid! How can I reason from there?
Andrzej Matuszewski's bidding problem: Q742 AJ7 A KJ984
Penalty would be non-standard. It means: points, that gives my pd maximum 2HCP.
How to avoid tragedy?
Serge is right in sense that large part of field automatically bids 1N. The latter contract seems to be easier for the hand and gives better score if we take 7 or 8 tricks for both contracts. This is why our situation is difficult.

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