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A Fatricide Squeeze
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Opponents reach a contract of 4 clubs and you are on lead with

 

North
AQ1063
Q108
10875
3

Not wanting to cash an Ace from AQ, or lead from the Queen of hearts, you decide on a passive club lead. (A diamond would have been better)

Dummy comes down with a dispiriting holding:

North
AQ1063
Q108
10875
3
East
K5
A962
AKQJ
J107

Declarer calls for the jack and takes partner's Queen with the Ace. He then leads 4 diamonds throwing the J8 as partner ruffs with the 9.

North
AQ1063
Q108
East
K5
A962
107

Partner leads a spade, declarer ruffs and then leads another club to the ten for partner to win with the King.

Partner now leads the J

North
AQ10
Q108
East
K5
A962

As can be seen, the jack of hearts lead transferred over control of both Hearts and Spades to the North Hand, and when Declarer won and led a trump, I graciously conceded the rest.

 

West
J8
K43
93
A86542
North
AQ1063
Q108
10875
3
East
K5
A962
AKQJ
J107
South
9742
J75
642
KQ9
D

Every bridge hand has some assets in it - they can be trick-taking assets, trumps, promoting and promotable cards and, what is important in this case - cards that can limit communications between declarer and dummy. Keeping a card that can beat dummy's highest card (to remove an entry), is fairly well known - but keeping a card that can beat dummy's second (or third) highest card, can also be important.

Squeeze defence isn't easy since you must place the cards and try and work out what declarer might be trying to do. Defenders can best spot potential positional squeezes by watching out for the BLUE conditions and try to prevent declarer from creating them.

B: One defender's cards must be BUSY - i.e. they have no idle cards they can discard.

L: Losers - declarer needs to get into a situation where they need all the tricks bar one.

U: Upper hand. there must be a squeeze card in the upper hand i.e sitting over the player to be squeezed.

E: Entry: there must be an entry into the upper hand to reach the squeeze card.

 

By leading the J south unfortunately created the (B) condition - all the other three were already present.

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