Bridge Winners comments by Gábor Szőts

World Youth Team Championships August 8-18 2018

Gábor Szőts

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The 14 IMP lost on tha last board averages to only 0.25 IMP/board. But USA1 lost 3.04 IMPs per board. That is what I think is too much (at least on an Edgar Kaplan scale).

Aug. 15

switching minors in non-leaping Michaels

Gábor Szőts

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(3m)-4♦

Aug. 15

switching minors in leaping Michaels over 2M

Gábor Szőts

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So it is forcing to game, while 4♣ is open to debate.

Aug. 15

switching minors in leaping Michaels over 2M

Gábor Szőts

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In my view the leaping michaels bid must be reserved to 4-5 losers. A wider range is unplayable because of the level. And if it is 4-5 losers then one slam invitation will do: you decline with 5 but accept with 4 losers.

Aug. 15

switching minors in leaping Michaels over 2M

Gábor Szőts

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What do you bid with ♥+♣?

Aug. 15

switching minors in leaping Michaels over 2M

Gábor Szőts

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I may be a pessimist but to play 4♦ as forcing does not seem sensible to me. They can easily double you in 5♦ while they must exercise some caution to double you in 4♦. And if they can double you in 4♦ you can be certain of a trump stack and play accordingly.
To play 4♦ forcing as a slam invitation does not seem necessary. You can use 4NT for that purpose.

Aug. 15

switching minors in leaping Michaels over 2M

Gábor Szőts

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Why have we inverted the minors?

Aug. 15

World Youth Team Championships August 8-18 2018

Gábor Szőts

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This will be hard to explain. Singapore-USA1 170-167.

Aug. 15

Gábor Szőts edited this comment Aug. 15

A brilliant bid by a Bridge Winners frequent poster

Gábor Szőts

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So they made a mistake. Now look what happens if Benoit bids 4♠: responder doubles (what else?), opener passes (what else?).

Aug. 14

Oren Kriegel's bidding problem: 2 J8752 AJT2 J75

Gábor Szőts

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I always read what you write. I never said they were identical situations. However, I am talking about the OP, not a hypothetic hand.

Aug. 14

A brilliant bid by a Bridge Winners frequent poster

Gábor Szőts

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Perhaps his idea was to make both opponents think his partner was short in clubs.

Aug. 13

A brilliant bid by a Bridge Winners frequent poster

Gábor Szőts

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Bidding 4♠ might also reach that goal. Bidding 2♣ might induce partner to make a fatal club lead.

Aug. 13

A brilliant bid by a Bridge Winners frequent poster

Gábor Szőts

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One of the opponents with short spades may have realized he had short spades.

Aug. 13

Defensive problem (mid-game)

Gábor Szőts

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♠3. For what I know declarer may have his 9 (1+3+3+2) tricks already. Let's cash out.

Aug. 13

Defensive problem (mid-game)

Gábor Szőts

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Leading back our ♠3 would also suggest a doubleton spade…

Aug. 13

Oren Kriegel's bidding problem: 2 J8752 AJT2 J75

Gábor Szőts

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Opener can't have 3 clubs because that would leave him with 4333 distribution, excluded by the premises.

Aug. 13

1!C balanced or !Cs with transfer responses, 1!D unbalanced

Gábor Szőts

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What do you do with a weak 5♦4♥ over 1♠?

Aug. 11

Is this sound?

Gábor Szőts

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1NT is minimum, misfit. Over 1♥, that is probably 3154 but I can picture 3163 too with weak ♦s. Over 1♠ it is a 4-card club or hearts suit. So practically as natural as can be.
I plan to play 2♣ Gazzilli where the weak variant is at least 55 in the minors (otherwise 1NT).

Aug. 9

Is this sound?

Gábor Szőts

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I am going to make proposals to one of my partners and I would like to go slowly.

Aug. 9

I have just read this - Fantunes

Gábor Szőts

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They don't have a code, they are innocent.

Aug. 9

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