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Is it really just 37%?

It is well known that odds for one suit to break 3-3 are close to 36%. Obviously if our opponents have less cards, bigger is chance of their 3-3 break. My question is what are odds of one suit to break 3-3 if some other suit already happened to be 3-3?

Some time ago I think I saw (in Imaginative Cardplay by Terence Reese) that if we know that one suit is 3-3, probability of other one being 3-3 is almost 50%, but then if I try to make formula and calculate it I get it is just a little above 37% and that if we know that two suits are 3-3 probability that third is 3-3 is just around 41%.

Here is that formula:

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